1221. 分割平衡字符串

    技术2022-09-01  71

    int balancedStringSplit(string s) { int cntOfL = 0, cntOfR = 0; int ret = 0; for (auto it:s) { if (it == 'L') cntOfL++; else if (it == 'R') cntOfR++; if (cntOfL == cntOfR) ret++, cntOfL = 0, cntOfR = 0; } return ret; }
    Processed: 0.010, SQL: 9