题目:[原题链接](https://leetcode-cn.com/problems/shortest-completing-word/(简单)
解法时间复杂度空间复杂度执行用时Ans 1 (Python) O ( N ) O(N) O(N) O ( 1 ) O(1) O(1)76ms (95.30%)Ans 2 (Python)Ans 3 (Python)LeetCode的Python执行用时随缘,只要时间复杂度没有明显差异,执行用时一般都在同一个量级,仅作参考意义。
解法一:
def shortestCompletingWord(self, licensePlate: str, words: List[str]) -> str: patterns = list(filter(str.isalpha, licensePlate.lower())) ans = " " * 15 for word in words: alpha = list(word) for p in patterns: if p not in alpha: break alpha.remove(p) else: if len(word) < len(ans): ans = word return ans