题目:
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note: 0 ≤ x, y < 231.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
代码:
class Solution {
public:
int hammingDistance(int x, int y) {
int res = 0;
for (int j = 0; j <= 31; j++) {
if ((x >> j & 1) ^(y >> j & 1))res += 1;
}
return res;
}
};