long length(char c
[]);
#include <stdio.h>
int main(int argc
, const char * argv
[]) {
long len
,i
;
char str
[30];
for (i
=0; i
<30; i
++) {
scanf("%c",&str
[i
]);
}
len
=length(str
);
printf("string has %ld characters.",len
);
return 0;
}
long length(char c
[])
{
char *p
=c
;
while (*p
!='#') {
p
++;
}
return p
-c
;
}
output:
123vgvcuvcuiwbcvvugvujkbb jb#
string has
28 characters
.Program ended with exit code
: 0
Processed:
0.009, SQL:
12
