上课部分
<a href
="${pageContext.request.contextPath}/user/toUpDate.do?id=${user.id}" class="btn bg-olive btn-xs">更新
</a
>
@RequestMapping("/toUpDate.do")
public ModelAndView
toUpDate(int id
){
User user
=userService
.selectUserById(id
);
ModelAndView modelAndView
= new ModelAndView();
modelAndView
.setViewName("user-update");
modelAndView
.addObject("user",user
);
return modelAndView
;
}
@Override
public User
selectUserById(int id
){
return userDao
.selectUserById(id
);
}
<select id
="selectUserById" parameterType
="int" resultType
="user">
select
* from tb_user where id
=#
{id
}
</select
>
这部分把user传到了update页面，是查询部分
作业部分
<form action
="${pageContext.request.contextPath}/user/UpDate.do"
method
="post">
@RequestMapping("/UpDate.do")
public String
UpDate(User user
){
userService
.UpDate(user
);
return "redirect:findAll.do";
}
@Override
public void UpDate(User user
) {
userDao
.UpDate(user
);
}
<update id
="UpDate" parameterType
="user">
update tb_user set username
=#
{username
},password
=#
{password
} where id
=#
{id
};
</update
>
把新的user值传过去更新，想了半小时没想出来同时传入老的和新的两个id的办法，所以这里写成id无法修改
效果图
