264. 丑数 II

    技术2022-07-11  75

    public int nthUglyNumber(int n) { if (n <= 0) return 0; if (n == 1) return 1; int[] dp = new int[n+1]; dp[1] = 1; int i2 = 1, i3 = 1, i5 = 1; for (int i = 2; i <= n; i++) { dp[i] = Math.min(2 * dp[i2], Math.min(3 * dp[i3], 5 * dp[i5])); if (dp[i] == 2 * dp[i2]) i2++; if (dp[i] == 3 * dp[i3]) i3++; if (dp[i] == 5 * dp[i5]) i5++; } return dp[n]; }
    Processed: 0.014, SQL: 9