题目原文
If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
代码
#include<iostream>
#include<cstdio>
using namespace std;
struct Money {
int Galleon;
int Sickle;
int Knut;
};
int main(void) {
struct Money P, A, D;
int sym = 0;
int flag = 0;
scanf("%d.%d.%d %d.%d.%d", &P.Galleon, &P.Sickle, &P.Knut, &A.Galleon, &A.Sickle, &A.Knut);
/*if (A.Galleon * 17 * 29 + A.Sickle * 29 + A.Knut < P.Galleon * 17 * 29 + P.Sickle * 29 + P.Knut) {
D = A;
A = P;
P = D;
sym = 1;
}*/
if (A.Knut + P.Knut >= 29) {
D.Knut = A.Knut + P.Knut - 29;
flag = 1;
}
else {
D.Knut = A.Knut + P.Knut;
}
if (flag == 1) {
A.Sickle++;
flag = 0;
}
if (A.Sickle + P.Sickle >= 17) {
D.Sickle = A.Sickle + P.Sickle-17; flag = 1;
}
else {
D.Sickle = A.Sickle + P.Sickle;
}
if (flag == 1) {
A.Galleon++;
flag = 0;
}
D.Galleon = A.Galleon + P.Galleon;
cout << D.Galleon << '.' << D.Sickle << '.' << D.Knut;
return 0;
}
