题目:原题链接(简单)
解法时间复杂度空间复杂度执行用时Ans 1 (Python) O ( N ) O(N) O(N) O ( 1 ) O(1) O(1)96ms (76.36%)Ans 2 (Python) O ( l o g N ) O(logN) O(logN) O ( 1 ) O(1) O(1)92ms (89.73%)Ans 3 (Python)LeetCode的Python执行用时随缘,只要时间复杂度没有明显差异,执行用时一般都在同一个量级,仅作参考意义。
解法一(遍历):
def peakIndexInMountainArray(self, A: List[int]) -> int: for i in range(len(A)): if A[i] > A[i + 1]: return i解法二(二分查找):
def peakIndexInMountainArray(self, A: List[int]) -> int: left = 0 right = len(A) - 1 while left < right: mid = (left + right) // 2 if A[mid] > A[mid + 1]: right = mid else: left = mid + 1 return left