e的倒数接近法，7可以继续换
(1+(-1/10**7))**(10**7)
np
.e
**-1
1/np
.e
def lnx(iter=7):
return (1+(-1/10**iter))**(10**iter)
lnx
(16),lnx
(7)
e函数
e
x
=
lim
(
1
+
x
n
)
n
e^{x} = \lim(1 + \frac{x}{n})^{n}
ex=lim(1+nx)n
∞
0
∞^0
∞0
np
.e
e
= 1/((1+(-1/10**7))**(10**7))
def e(iter=7):
return 1/((1+(-1/10**iter))**(10**iter))
e
()
Processed:
0.017, SQL:
10
