6-5 多重继承派生类构造函数 (10分)
根据所给的基类Student和Teacher，定义Graduate类
类定义：
#include <iostream>
#include <string>
using namespace std;
class Teacher
{public:
Teacher(string nam,int a,string t)
{name=nam;
age=a;
title=t;}
void display()
{cout<<"name:"<<name<<endl;
cout<<"age"<<age<<endl;
cout<<"title:"<<title<<endl;
}
protected:
string name;
int age;
string title;
};
class Student
{public:
Student(string nam,char s,float sco)
{name1=nam;
sex=s;
score=sco;}
void display1()
{cout<<"name:"<<name1<<endl;
cout<<"sex:"<<sex<<endl;
cout<<"score:"<<score<<endl;
}
protected:
string name1;
char sex;
float score;
};
/* 请在这里填写答案 */
裁判测试程序样例：
int main( )
{Graduate grad1("Wang-li",24,'f',"assistant",89.5,1234.5);
grad1.show( );
return 0;
}
输出样例：
name:Wang-li
age:24
sex:f
score:89.5
title:assistant
wages:1234.5
代码实现：
class Graduate:public Teacher,public Student//多重继承的形式
{
protected:
double wages;
public:
Graduate(string nam,int a,char s,string t,float sco,float w):Teacher(nam,a,t),Student(nam,s,sco),wages(w)
{
//两个类的name都要初始化，哪怕有两个
}
void show()
{
cout<<"name:"<<name<<endl;//基类的成员函数是保护的，不是私有的，所以可以直接访问
cout<<"age:"<<age<<endl;
cout<<"sex:"<<sex<<endl;
cout<<"score:"<<score<<endl;
cout<<"title:"<<title<<endl;
cout<<"wages:"<<wages<<endl;
}
};
以上均为个人的小观点和小看法，如有不对的地方，还望赐教。
