LeetCode题解(0892)：三维形体的表面积(Python)

题目：原题链接（简单）

解法时间复杂度空间复杂度执行用时Ans 1 (Python)$O(N^2)$$O(1)$116ms (68.17%)Ans 2 (Python)Ans 3 (Python)

LeetCode的Python执行用时随缘，只要时间复杂度没有明显差异，执行用时一般都在同一个量级，仅作参考意义。

解法一：

def surfaceArea(self, grid: List[List[int]]) -> int: size = len(grid) ans = 0 for i in range(size): for j in range(size): if grid[i][j]: ans += 2 if i == 0: ans += grid[i][j] elif grid[i][j] > grid[i - 1][j]: ans += grid[i][j] - grid[i - 1][j] if i == size - 1: ans += grid[i][j] elif grid[i][j] > grid[i + 1][j]: ans += grid[i][j] - grid[i + 1][j] if j == 0: ans += grid[i][j] elif grid[i][j] > grid[i][j - 1]: ans += grid[i][j] - grid[i][j - 1] if j == size - 1: ans += grid[i][j] elif grid[i][j] > grid[i][j + 1]: ans += grid[i][j] - grid[i][j + 1] return ans