LeetCode46:全排列

    技术2022-07-17  63

    class Solution { public List<List<Integer>> permute(int[] nums) { //创建结果数组 List<List<Integer>> ans = new ArrayList<>(); //回溯 backtrack(nums,new ArrayList<Integer>(),ans); return ans; } //回溯方法 public void backtrack(int[] nums,ArrayList<Integer>track,List<List<Integer>> ans){ //满足条件 if(track.size() == nums.length){ ans.add(new ArrayList<>(track)); } //选择 for(int i = 0;i < nums.length;i++){ if(track.contains(nums[i])) continue; //做选择 track.add(nums[i]); //回溯 backtrack(nums,track,ans); //撤销选择 track.remove(track.size()-1); } } }

     

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