6-6 计算两数的和与差 (10分) 本题要求实现一个计算输入的两数的和与差的简单函数。
函数接口定义： void sum_diff( float op1, float op2, float *psum, float *pdiff ); 其中op1和op2是输入的两个实数，psum和pdiff是计算得出的和与差。
在这里插入代码片 #include <stdio.h> void sum_diff( float op1, float op2, float *psum, float *pdiff ); int main() { float a, b, sum, diff; scanf("%f %f", &a, &b); sum_diff(a, b, &sum, &diff); printf("The sum is %.2f\nThe diff is %.2f\n", sum, diff); return 0; } void sum_diff( float op1, float op2, float *psum, float *pdiff ) { *psum=op1+op2; *pdiff=op1-op2; }