快速排序代码备份

    技术2022-07-20  72

    # def kuaipai(a,b): # if a>=b:return None # i = a # j = b # temp = list1[i] # while i!=j: # while list1[j]>=temp and i!=j:j-=1 # list1[i],list1[j] = list1[j],list1[i] # while list1[i]<=temp and i!=j:i+=1 # list1[i],list1[j] = list1[j],list1[i] # list1[i]=temp # kuaipai(a,i-1) # kuaipai(i+1,b) # list1 = [1,5,6,4,7,2,8,3,4,2,6,9,0,3] # kuaipai(0,len(list1)-1)
    Processed: 0.009, SQL: 9