如何取出一组字符串中的数字（整数或小数）
import re >>> s = '4 and 10.2356' >>> re.findall(r'\d+(?:\.\d+)?', s) ['4', '10.2356'] >>> print(int(re.findall(r'\d+(?:\.\d+)?', s)[0])) 4 >>> print(float(re.findall(r'\d+(?:\.\d+)?', s)[1])) 10.2356 \d+： matches one or more digits.\d+.\d+ ：matches one or more digits plus any single character plus one or more digits.\d+.\d+ ：matches one or more digit characters pus a literal dot plus one or more digits.\d+(?:.\d+)? ：matches integer as well as floating point numbers because we made the pattern which matches the decimal part as optional. ? after a capturing or non-capturing group would turn the whole group to an optional one.