LeetCode题解(1154)：判断日期在一年中的第几天(Python)

题目：原题链接（简单）

解法时间复杂度空间复杂度执行用时Ans 1 (Python)$O(1)$$O(1)$32ms (96.43%)Ans 2 (Python)$O(1)$$O(1)$40ms (72.62%)Ans 3 (Python)

LeetCode的Python执行用时随缘，只要时间复杂度没有明显差异，执行用时一般都在同一个量级，仅作参考意义。

解法一：

def dayOfYear(self, date: str) -> int: year, month, date = date.split("-") year, month, date = int(year), int(month), int(date) leap = year % 4 == 0 and (year % 100 != 0 or year % 400 == 0) if leap: month_days = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] else: month_days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] return sum(month_days[:month - 1]) + date

解法二（优雅化）：

def dayOfYear(self, date: str) -> int: year, month, date = map(int, date.split("-")) if year % 4 == 0 and (year % 100 != 0 or year % 400 == 0): month_days = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] else: month_days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] return sum(month_days[:month - 1]) + date