力扣题,二叉树的翻转python
class TreeNode:
def __init__(self
, x
):
self
.val
= x
self
.left
= None
self
.right
= None
class Solution:
def invertTree(self
, root
):
if not root
:
return None
root
.left
,root
.right
=self
.invertTree
(root
.right
),self
.invertTree
(root
.left
)
return root
题目原址
转载请注明原文地址:https://ipadbbs.8miu.com/read-46565.html