"""
@Author ： 侬&码
"""
from functools import reduce
num1 = 1125
num2 = 855
mi = min(num1, num2)
print(mi)
li = []
count = 0
while True:
for i in range(2, mi + 1):
if num1 % i == 0 and num2 % i == 0:
num1, num2 = num1 // i, num2 // i
mi = min(num1, num2)
li.append(i)
break
count += 1
else:
break
p1 = reduce(lambda x, y: x * y, li)
print(f'最大公约数：{p1},最大公倍数：{p1 * num1 * num2}')
print('执行内循环次数：', count)
Processed:
0.010, SQL:
9
