PAT基础编程题目-6-8 简单阶乘计算
题目详情
题目地址：https://pintia.cn/problem-sets/14/problems/740
解答
C语言版
#include <stdio.h>
int Factorial(const int N
);
int main()
{
int N
, NF
;
scanf("%d", &N
);
NF
= Factorial(N
);
if (NF
) printf("%d! = %d\n", N
, NF
);
else printf("Invalid input\n");
return 0;
}
int Factorial(const int N
) {
int product
= 1;
if (N
>= 0) {
for (int i
= 2; i
<= N
; i
++)
product
= product
* i
;
return product
;
}
return 0;
}
C++版
#include<iostream>
using namespace std
;
int Factorial(const int N
);
int main() {
int N
, NF
;
cin
>> N
;
NF
= Factorial(N
);
if (NF
) cout
<< N
<<"! = " << NF
<<endl
;
else cout
<< "Invalid input"<<endl
;
return 0;
}
int Factorial(const int N
) {
int product
= 1;
if (N
>= 0) {
for (int i
= 2; i
<= N
; i
++)
product
= product
* i
;
return product
;
}
return 0;
}
Java版
public class Main{
private static int Factorial(final int N
) {
int product
= 1;
if(N
>=0) {
for (int i
= 2; i
<= N
; i
++) {
product
= product
*i
;
}
return product
;
}
return 0;
}
public static void main(String
[] args
) {
int N
=0,NF
=0;
Scanner scanner
= new Scanner(System
.in
);
if(scanner
.hasNext()) {
N
= scanner
.nextInt();
}
scanner
.close();
NF
= Factorial(N
);
if(NF
>0)
System
.out
.println(N
+"!="+NF
);
else {
System
.out
.println("Invalid input");
}
}
}
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