[C++] PAT 1022 Digital Library (30分)

Sample Input:

3 1111111 The Testing Book Yue Chen test code debug sort keywords ZUCS Print 2011 3333333 Another Testing Book Yue Chen test code sort keywords ZUCS Print2 2012 2222222 The Testing Book CYLL keywords debug book ZUCS Print2 2011 6 1: The Testing Book 2: Yue Chen 3: keywords 4: ZUCS Print 5: 2011 3: blablabla

Sample Output:

1: The Testing Book 1111111 2222222 2: Yue Chen 1111111 3333333 3: keywords 1111111 2222222 3333333 4: ZUCS Print 1111111 5: 2011 1111111 2222222 3: blablabla Not Found

题解：

该题使用map<string,set<int>>将相同信息与id集对应

#include <iostream> #include <string> #include <map> #include <set> using namespace std; int n; map<string,set<int>> title,author,keywords,publisher,year; void query(map<string,set<int>> &m,string &str){ if(m.find(str) != m.end()){ for(set<int>::iterator i = m[str].begin();i !=m[str].end();i++){ printf("%07d\n",*i); } }else{ cout << "Not Found" << endl; } } int main(){ cin >> n; int id; string t_title,t_author,t_key,t_publisher,t_year; for(int i=0;i<n;i++){ cin >> id; getchar(); getline(cin,t_title); title[t_title].insert(id); getline(cin,t_author); author[t_author].insert(id); while(cin >> t_key){ keywords[t_key].insert(id); char c =getchar(); if(c == '\n'){ break; } } getline(cin,t_publisher); publisher[t_publisher].insert(id); getline(cin,t_year); year[t_year].insert(id); } int m; cin >> m; int num; string q; for(int i=0;i<m;i++){ scanf_s("%d: ",&num); getline(cin,q); cout << num << ": " << q << endl; if(num == 1) query(title,q); else if(num == 2) query(author,q); else if(num == 3) query(keywords,q); else if(num == 4) query(publisher,q); else if(num == 5) query(year,q); } system("pause"); return 0; }