基于 Maven 创建 war 工程
1.创建 maven 项目2.创建 webapp 文件夹3.配置 web 模块4.配置 pom.xml
1.创建 maven 项目
2.创建 webapp 文件夹
在 src/main 下新建 webapp 文件夹在 webapp 下新建 WEB-INF 文件夹在 WEB-INF 下新建 web.xml
3.配置 web 模块
如果不配置会导致无法新建 jsp 文件菜单 --> Project Structure -->
4.配置 pom.xml
<?xml version
="1.0" encoding
="UTF-8"?>
<project xmlns
="http://maven.apache.org/POM/4.0.0"
xmlns
:xsi
="http://www.w3.org/2001/XMLSchema-instance"
xsi
:schemaLocation
="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion
>
<groupId>com
.dqcgm
</groupId
>
<artifactId>mavenDemo
</artifactId
>
<version>1.0-SNAPSHOT
</version
>
<packaging>war
</packaging
>
<dependencies>
<dependency>
<groupId>javax
.servlet
</groupId
>
<artifactId>javax
.servlet
-api
</artifactId
>
<version>3.1.0</version
>
<scope>provided
</scope
>
</dependency
>
<dependency>
<groupId>javax
.servlet
.jsp
</groupId
>
<artifactId>jsp
-api
</artifactId
>
<version>2.2</version
>
<scope>provided
</scope
>
</dependency
>
<dependency>
<groupId>jstl
</groupId
>
<artifactId>jstl
</artifactId
>
<version>1.2</version
>
</dependency
>
</dependencies
>
<build>
<plugins>
<plugin>
<groupId>org
.apache
.tomcat
.maven
</groupId
>
<artifactId>tomcat7
-maven
-plugin
</artifactId
>
<version>2.2</version
>
<configuration>
<path>/</path
>
<port>8080</port
>
</configuration
>
</plugin
>
</plugins
>
</build
>
</project
>
