【数据库】178. 分数排名

    技术2025-07-19  8

    1 题目描述

    2 解题思路

    这个真的不太懂哦。。。

    3 解决代码

    # Write your MySQL query statement below select s1.Score,count(distinct s2.Score) `Rank` from Scores s1 left join Scores s2 on s1.Score <= s2.Score group by s1.Id order by s1.Score desc
    Processed: 0.011, SQL: 9