和 IsDebuggerPresent 差不多简单的反调试技术 👀
BOOL bIsDbgPresent
= FALSE
;
if(CheckRemoteDebuggerPresent(GetCurrentProcess(), &bIsDbgPresent
) != 0){
if(bIsDbgPresent
== TRUE
){
cout
<< "发现调试器" << endl
;
}
else{
cout
<< "没有调试器" << endl
;
}
}
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