和 IsDebuggerPresent 差不多简单的反调试技术 👀
 
BOOL bIsDbgPresent 
= FALSE
;
if(CheckRemoteDebuggerPresent(GetCurrentProcess(), &bIsDbgPresent
) != 0){
	if(bIsDbgPresent 
== TRUE
){
		cout 
<< "发现调试器" << endl
;
	}
	else{
		cout 
<< "没有调试器" << endl
;
	}
}
                
                
                
        
    
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