编写一个函数，实现位数组

#include <stdio.h> void set_bit(char bit_array[],unsigned bit_number); void clear_bit(char bit_array[],unsigned bit_number); void assign_bit(char bit_array[],unsigned bit_number,int value); int test_bit(char bit_array[],unsigned bit_number); int main(int argc, const char *argv[]) { char a[20]="abcdefghi"; int b = 1; int c = 2; int d = 3; set_bit(a,b); clear_bit(a,c); assign_bit(a,d,1); printf("%d\n",test_bit(a,b)); printf("%s\n",a); return 0; } /* 把指定位置１ */ void set_bit(char bit_array[],unsigned bit_number) { bit_array[bit_number] = 1; } /* 把指定为淸0 */ void clear_bit(char bit_array[],unsigned bit_number) { bit_array[bit_number] = 0; } /* 如果value的值为０,把指定的位淸0，否则置1 */ void assign_bit(char bit_array[],unsigned bit_number,int value) { if(value == 0){ bit_array[bit_number] = 0; }else { bit_array[bit_number] = 1; } } /* 指定的位不是0，函数返回真，否则返回假 */ int test_bit(char bit_array[],unsigned bit_number) { if(bit_array[bit_number] != 0){ return 1; }else { return 0; } }