PAT基础编程题目-7-3 逆序的三位数
题目详情
题目地址：https://pintia.cn/problem-sets/14/problems/783
解答
C语言版
#include<stdio.h>
int main() {
int array
[3];
int number
;
scanf("%d", &number
);
for (int i
= 0; i
< 3; i
++)
{
array
[i
] = number
% 10;
number
= number
/ 10;
}
for (int j
= 0; j
< 3; j
++)
{
if (array
[j
] || (array
[1]==0 && array
[0]!=0) )
printf("%d", array
[j
]);
}
return 0;
}
C++版
#include<iostream>
using namespace std
;
int main() {
int array
[3];
int number
;
cin
>> number
;
for (int i
= 0; i
< 3; i
++)
{
array
[i
] = number
% 10;
number
= number
/ 10;
}
for (int j
= 0; j
< 3; j
++)
{
if (array
[j
] || (array
[1] == 0 && array
[0] != 0))
cout
<< array
[j
];
}
return 0;
}
Java版
import java
.util
.Scanner
;
public class Main{
public static void main(String
[] args
) {
int number
= 0;
int [] array
= new int[3];
Scanner scanner
= new Scanner(System
.in
);
if(scanner
.hasNext()) {
number
= scanner
.nextInt();
}
scanner
.close();
for (int i
= 0; i
< array
.length
; i
++) {
array
[i
] = number
%10;
number
= number
/10;
}
for (int j
= 0; j
< array
.length
; j
++) {
if (array
[j
]!=0 || (array
[1]==0 && array
[0]!=0)) {
System
.out
.print(array
[j
]);
}
}
}
}
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