xiaojinlong上传案例

    技术2022-07-10  138

    # #已知身体质量指数(BMI)的计算公式为BMI=体重/身高平方, # # (体重的单位为“千克”,身高的单位为“米”)BMI<18.5为,“偏瘦” # # 18.5<=BMI< 24为正常,24<=BMI< 28位“偏胖”,BMI>=28为,肥胖。? # h = int(input("请输入你的身高,单位为cm:")) # w = float(input("请输入你的体重kg:")) # bmi = w/(h/100)**2 # if bmi < 18.5: # print('偏瘦') # elif 18.5 <= bmi < 24: # print('正常') # elif 24 <= bmi < 28: # print('偏胖') # elif bmi >= 28: # print("肥胖") # else: # print('请检查一下你是否输入正确!') # 综合温度和风速的数据判断天气情况 # w = float(input('请输入温度:')) # s = float(input("请输入风速:")) # if w > 25: # if s > 8: # print('天热,风大') # else: # print('天热,风小') # else: # if s > 8: # print('天冷,风大') # else: # print('天冷,风小') # # dict1 = {'姓名':'张三','性别':'女','地址':'毕节'} # # for k,v in dict1.items(): # print('{},{}'.format(k,v)) # while True: # height = float(input('请输入身高,单位为米')) # if height < 0.3: # print("你孩子太小,不用收费") # elif height > 2.5: # print("你输入错误,这个身高不正常") # else: # l_price = 200 # if height <= 1.4: # print('你门票实际价格{},节约{}'.format(l_price / 2, l_price - l_price / 2)) # else: # print('你门票实际价格{},节约{}'.format(l_price * 0.9, l_price - l_price * 0.9)) # break # i = 20 # # while i > 0 : # print(i) # i=i-1 # i =100 # sum = 0 # while i >0: # sum =sum+i # i=i-1 # # print(sum) # i = 5 # sum = 0 # while i <= 100: # print(i) # sum =sum+i # i+=5 # print('循环体内代码') # print(sum) # x = y = z =1 # z = 1 # y = 1 # # x = 1 # # x,y = y ,x # # x = x+y # 石头剪刀布案例 # import random # # temp = int(input("请选择你的手势【0】:石头,【1】:剪刀,【2】:布")) # c = random.randint(0,2) # if temp not in [0,1,2]: # print('你神经病,乱搞') # elif (temp==0 and c==1) or (temp == 1 and c == 2) or (temp ==2 and c==0): # print('电脑出的手势是',c) # print('你战胜电脑') # elif (temp==0 and c==0) or (temp == 1 and c == 1) or (temp ==2 and c==2): # print('电脑出的手势是', c) # print('平手') # else: # print('电脑出的手势是', c) # print('你输了') # # for嵌套,for和while 都可以嵌套,例如下列案例。 # for i in range(1,10): # for j in range(1,i+1): # print("{}*{}={}".format(j,i,i*j),end= ' ') # print('\n') # i=1 # while i<100: # print("*"*i) # i+=1 # # for i in range(1,11): # print('*'*i) # j = 10//2 # for i in range(1,10,2): # print(' '*j,end='') # j-=1 # print('*'*i) #打印等腰三角形图形 # j=5 # for i in range(1,10,2): # print(" "*j,end="") # j-=1 # print("*"*i) #案例:9*9乘法表打印 # for i in range(1,10): # for j in range(1,i+1): # print("{}*{}={}".format(j,i,i*j),end=' ') # print('\n') # # for i in range(50): # print(i) # i=0 # while True: # i+=1 # if i==50: # continue # elif i==100: # break # print(i) #案例: 打印1–100数字,但是遇到5,或者是5的倍数就跳过。代码如下: # for i in range(1,101): # if i==5 or i%5 ==0 or i//10==5: # continue # else: # print(i) # a=0 # if a>0: # print(a) # for i in range(1,10): # print(i) # print(a) # # 案例判断是否是合法的邮件地址,且提取用户名和服务器地址 # temp1 = input("请输入一个邮箱地址") # # if temp1.find('@') == -1: # print("请输入正确的邮箱地址:") # elif temp1.find('@') == 0: # print("邮箱第一个字符不能为@:") # elif temp1.find('@') == len(temp1) - 1: # print('@不能结尾,请输入正确邮箱') # else: # print('用户名为:{},邮箱服务器地址:{}'.format(temp1.split("@")[0], temp1.split("@")[1])) # 字符串:“”,‘’,'''三引号''' # str1 = ' nykingkun@126.com' # str2 = "nykingkun@126.com" # str3 = '''nykingkun@126.com''' # temp = str1.find('@') # print(temp) # temp1 =str1[::-1] # print(temp1) # print(str1.find('@')) # print(str1.count('n')) # temp = str1.split('@') # print(temp[0],temp[1]) #案例:请输入一个邮箱地址:判断邮箱是否合法,提取出其中的用户名和服务器地址 # # temp = input("请输入一个邮箱地址:") # if temp.find("@")==0: # print('第一个字符不能是@!') # elif temp.find('@')==-1: # print("你的邮箱地址错误,没有符号@!") # elif temp.find('@')==len(temp)-1: # print('邮箱最后一个字符不能是@!') # else: # a = temp.split("@") # print('你的用户名为:{},你的服务器地址为:{}'.format(a[0],a[1])) # str1 = 'abc' # # if 'a' not in str1: # print('a在str1中') # else: # print('没在') #字符串:什么是字符串 #字符串常见的内建函数 # str.format() # str.find() # str.index() # str.count() # str.split() # str.capitalize() # str.replace() # str.isdigit() #字符串计算 # + * # in not #字符串下标 #字符串 # str1 = 'kingkun@ 126.com' # temp = str1.split('') # print(temp) #查询模块 # dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} # for k,v in dict2.items(): # print(k,v) # # print('---'*10) #增加模块 # input1 = input('请输入你要添加的姓名') # gender = input("请输入性别") # age = int(input('请输入你的年龄')) # address = input('请输入地址') # temp_list = [gender,age,address] # dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} # dict2[input1] = temp_list # for k,v in dict2.items(): # print(k,v) #删除数据模块 # dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} # for k,v in dict2.items(): # print(k,v) # print('-'*14) # del dict2['张三'] # for k,v in dict2.items(): # print(k,v) #修改模块 # dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} # for k,v in dict2.items(): # print(k,v) # print('-'*14) # # input1 = input('请输入你要修改的姓名') # gender = input("请输入修改后性别") # age = int(input('请输入修改后你的年龄')) # address = input('请输入修改后地址') # temp_list = [gender,age,address] # dict2[input1] = temp_list # for k,v in dict2.items(): # print(k,v) # dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} # # while True: # str1 = '学生管理系统' # print(str1.center(35)) # print('0:查询,1:添加,2:删除,3:修改,4:退出') # a = int(input("请输入你要选择的操作:")) # if a == 0: # for k, v in dict2.items(): # print(k, v) # elif a == 1: # input1 = input('请输入你要添加的姓名') # gender = input("请输入性别") # age = int(input('请输入你的年龄')) # address = input('请输入地址') # temp_list = [gender, age, address] # dict2[input1] = temp_list # for k, v in dict2.items(): # print(k, v) # elif a == 2: # temp = input("请输入你要删除的姓名") # for k, v in dict2.items(): # print(k, v) # print('-' * 14) # del dict2[temp] # for k, v in dict2.items(): # print(k, v) # elif a == 3: # for k, v in dict2.items(): # print(k, v) # print('-' * 14) # input1 = input('请输入你要修改的姓名') # gender = input("请输入修改后性别") # age = int(input('请输入修改后你的年龄')) # address = input('请输入修改后地址') # temp_list = [gender, age, address] # dict2[input1] = temp_list # for k, v in dict2.items(): # print(k, v) # elif a==4: # break # 学生管理系统案例 # dict1 = {'姓名':['性别','年龄','地址']} # while True: # print("*"*10,'学生管理系统',"*"*10) # temp = int(input("查看学生信息请选择0,添加请选择1,删除请选择2,修改请选择3,退出选择4:")) # if temp ==0: # for k,v in dict1.items(): # print(k,v) # elif temp == 1: # name = input("请输入学生姓名:") # gender = input("请输入学生性别:") # age = input("请输入学生数字年龄:") # address = input('请输入学生地址:') # lis_temp = [] # lis_temp.append(gender) # lis_temp.append(age) # lis_temp.append(address) # dict1[name] = lis_temp # print('你成功添加"{}"信息,所以信息如下:'.format(name)) # for k, v in dict1.items(): # print(k, v) # elif temp ==2: # name = input("请输入需要删除学生姓名:") # del dict1[name] # print('移除成功') # for k, v in dict1.items(): # print(k, v) # elif temp ==3: # name = input("请输入需要修改学生姓名,如果要修改姓名请删除重新添加:") # dict1[name][0]=input("请输入修改学生性别:") # dict1[name][1] = input("请输入修改学生数字年龄:") # dict1[name][2] = input('请输入修改学生地址:') # print('修改成功') # for k, v in dict1.items(): # print(k, v) # elif temp ==4: # break # #查询 # list1 = ['字符串',10,['abc']] # print(list1[2])#使用下标进行查询,下标从0开始 # # #增加 # list1 = ['字符串',10,['abc']] # temp= 'aaaa' # list1.append(temp)#结尾增加元素 # print(list1) #插入 # list1 = ['字符串',10,['abc']] # print('原来的字符串',list1) # temp = 'aaaa' # list1.insert(1,temp)#在指定位置删除元素 # print('插入后字符串',list1) #修改 # list1 = ['字符串',10,['abc']] # print('原来的字符串',list1) # temp = 'aaaa' # list1[1]=11 # print('插入后字符串',list1) #删除 # list1 = ['字符串',10,['abc']] # print('原来的字符串',list1) # list1.remove(10)#移除指定元素 # list1.pop(0)#弹出指定元素,如果不带参数,弹出最后一个 # print('删除后字符串',list1) #元组 # tuple1 = (1,2,3,4) # for i in tuple1: # print(i) # #元组(不能修改)但是有嵌套(嵌套内部可以修改)的一定要注意 # tuple1 = (1,2,3,4,[1,2,4]) # print(tuple1) # tuple1[4][2]=3 # print(tuple1) # #集合案例 集合是无序的,没有下标,不能用下标索引。 # list1 = [1,2,3,4,5,6,1,2,3,4,5,6,7,] # set1 = {1,2,3,4,5,6,1,2,3,4,5,6,7} # tuple = (1,2,3,4,5,6,1,2,3,4,5,6,7,) # # temp = set(tuple) # temp2 = list(set1) # print(temp) # print(temp2) # # set1.pop() # # list1.pop() # 字典:{'key':'value'} # 函数:系统内置函数,自定义函数 # print() # input() # 案例自定义函数:带参数,不带参数,带返回值,不带返回值 # def sum_1(): # a=1 # b=2 # print(a+b) # 案例带参数,并且默认参数 # def sum_2(a=0,b=0): # print(a+b) # 案例 带参数:默认,1个参数,多个参数,不定长参数。 # def add(a,b): # print(a+b) # def abc(*args,**kwargs): # if len(args) > 1: # print(sum(args)) # else: # print(kwargs) # 不定长参数案例 # def abc(a,b,*args,**kwargs):#定义可变长函数 # print("参数a={},b={},args={},kwargs={}".format(a,b,args,kwargs)) # # abc(1,2,3,4,5,6,7,[1,2,3,],(1,2,3),p=0,k=1) #函数调用 #带返回值函数 # 带参数+带返回值 # def add(a,b): # temp = a+b # return temp # # print(add(1,2)) # 无参数,有返回值 # def add(): # a=10 # b=20 # return a+b # # temp = add() # print(temp) #无参数,有返回值 # def abc(): # return {"abc":10} # # temp = abc() # # print(temp) # 有参数,有返回值 # def abc(a,b): # return {a:b} # # temp = abc('king',10) # # print(temp) # 学生管理系统案例(函数版本) dict1 = {'姓名':['性别','年龄','地址'],'King':['men',10,'毕节']} temp=0 def suru(): """这个函数的目的是输入选择数字""" print("0:查询,1:增加,2:删除,3:修改,4:退出") global temp temp = int(input("请输入一个数字")) def chaxun(): """查询数据库中的信息""" for k,v in dict1.items(): print(k,v) def abc(): '''添加到数据库''' xingbie = input('请输入性别') nianl = input("请输入年龄") dizhi = input("请输入地址") dict1[xingming] = [xingbie, nianl, dizhi] while True: suru() if temp == 0: chaxun() elif temp == 1: xingming = input("请输入要添加的姓名") abc() chaxun() elif temp == 2: xingming = input("请输入要添加的姓名") if xingming in dict1.keys(): del dict1[xingming] else: print('没有此人,无法删除') chaxun() elif temp == 3: xingming = input("请输入要添加的姓名") if xingming in dict1.keys(): abc() chaxun() else: print('没有此人,无法修改') elif temp == 4: break else: print("你输入错误,请重新输入")
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