python部分案例代码

    技术2022-07-11  117

    # (体重的单位为“千克”,身高的单位为“米”)BMI<18.5为,“偏瘦” # 18.5<=BMI< 24为正常,24<=BMI< 28位“偏胖”,BMI>=28为,肥胖。? h = int(input("请输入你的身高,单位为cm:")) w = float(input("请输入你的体重kg:")) bmi = w/(h/100)**2 if bmi < 18.5: print('偏瘦') elif 18.5 <= bmi < 24: print('正常') elif 24 <= bmi < 28: print('偏胖') elif bmi >= 28: print("肥胖") else: print('请检查一下你是否输入正确!') # 综合温度和风速的数据判断天气情况 w = float(input('请输入温度:')) s = float(input("请输入风速:")) if w > 25: if s > 8: print('天热,风大') else: print('天热,风小') else: if s > 8: print('天冷,风大') else: print('天冷,风小') # # dict1 = {'姓名':'张三','性别':'女','地址':'毕节'} # # for k,v in dict1.items(): # print('{},{}'.format(k,v)) while True: height = float(input('请输入身高,单位为米')) if height < 0.3: print("你孩子太小,不用收费") elif height > 2.5: print("你输入错误,这个身高不正常") else: l_price = 200 if height <= 1.4: print('你门票实际价格{},节约{}'.format(l_price / 2, l_price - l_price / 2)) else: print('你门票实际价格{},节约{}'.format(l_price * 0.9, l_price - l_price * 0.9)) break # i = 20 # # while i > 0 : # print(i) # i=i-1 # i =100 # sum = 0 # while i >0: # sum =sum+i # i=i-1 # # print(sum) i = 5 sum = 0 while i <= 100: print(i) sum =sum+i i+=5 print('循环体内代码') # print(sum) # x = y = z =1 # z = 1 # y = 1 # # x = 1 # # x,y = y ,x # # x = x+y # 石头剪刀布案例 import random temp = int(input("请选择你的手势【0】:石头,【1】:剪刀,【2】:布")) c = random.randint(0,2) if temp not in [0,1,2]: print('你神经病,乱搞') elif (temp==0 and c==1) or (temp == 1 and c == 2) or (temp ==2 and c==0): print('电脑出的手势是',c) print('你战胜电脑') elif (temp==0 and c==0) or (temp == 1 and c == 1) or (temp ==2 and c==2): print('电脑出的手势是', c) print('平手') else: print('电脑出的手势是', c) print('你输了') # # for嵌套,for和while 都可以嵌套,例如下列案例。 for i in range(1,10): for j in range(1,i+1): print("{}*{}={}".format(j,i,i*j),end= ' ') print('\n') # i=1 # while i<100: # print("*"*i) # i+=1 # # for i in range(1,11): # print('*'*i) # j = 10//2 # for i in range(1,10,2): # print(' '*j,end='') # j-=1 # print('*'*i) #打印等腰三角形图形 j=5 for i in range(1,10,2): print(" "*j,end="") j-=1 print("*"*i) #案例:9*9乘法表打印 for i in range(1,10): for j in range(1,i+1): print("{}*{}={}".format(j,i,i*j),end=' ') print('\n') for i in range(50): print(i) i=0 while True: i+=1 if i==50: continue elif i==100: break print(i) #案例: 打印1–100数字,但是遇到5,或者是5的倍数就跳过。代码如下: for i in range(1,101): if i==5 or i%5 ==0 or i//10==5: continue else: print(i) a=0 if a>0: print(a) for i in range(1,10): print(i) print(a) # # 案例判断是否是合法的邮件地址,且提取用户名和服务器地址 temp1 = input("请输入一个邮箱地址") if temp1.find('@') == -1: print("请输入正确的邮箱地址:") elif temp1.find('@') == 0: print("邮箱第一个字符不能为@:") elif temp1.find('@') == len(temp1) - 1: print('@不能结尾,请输入正确邮箱') else: print('用户名为:{},邮箱服务器地址:{}'.format(temp1.split("@")[0], temp1.split("@")[1])) # 字符串:“”,‘’,'''三引号''' # str1 = ' nykingkun@126.com' # str2 = "nykingkun@126.com" # str3 = '''nykingkun@126.com''' # temp = str1.find('@') # print(temp) # temp1 =str1[::-1] # print(temp1) # print(str1.find('@')) # print(str1.count('n')) # temp = str1.split('@') # print(temp[0],temp[1]) #案例:请输入一个邮箱地址:判断邮箱是否合法,提取出其中的用户名和服务器地址 # temp = input("请输入一个邮箱地址:") if temp.find("@")==0: print('第一个字符不能是@!') elif temp.find('@')==-1: print("你的邮箱地址错误,没有符号@!") elif temp.find('@')==len(temp)-1: print('邮箱最后一个字符不能是@!') else: a = temp.split("@") print('你的用户名为:{},你的服务器地址为:{}'.format(a[0],a[1])) str1 = 'abc' if 'a' not in str1: print('a在str1中') else: print('没在') #字符串:什么是字符串 #字符串常见的内建函数 # str.format() # str.find() # str.index() # str.count() # str.split() # str.capitalize() # str.replace() # str.isdigit() #字符串计算 # + * # in not #字符串下标 #字符串 # str1 = 'kingkun@ 126.com' # temp = str1.split('') # print(temp) #查询模块 dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} for k,v in dict2.items(): print(k,v) print('---'*10) #增加模块 input1 = input('请输入你要添加的姓名') gender = input("请输入性别") age = int(input('请输入你的年龄')) address = input('请输入地址') temp_list = [gender,age,address] dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} dict2[input1] = temp_list for k,v in dict2.items(): print(k,v) #删除数据模块 dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} for k,v in dict2.items(): print(k,v) print('-'*14) del dict2['张三'] for k,v in dict2.items(): print(k,v) #修改模块 dict2 = {'张三':['男',60,'毕节'],'李四':['男',50,'贵阳']} for k,v in dict2.items(): print(k,v) print('-'*14) input1 = input('请输入你要修改的姓名') gender = input("请输入修改后性别") age = int(input('请输入修改后你的年龄')) address = input('请输入修改后地址') temp_list = [gender,age,address] dict2[input1] = temp_list for k,v in dict2.items(): print(k,v) # 学生管理系统案例 dict1 = {'姓名':['性别','年龄','地址']} while True: print("*"*10,'学生管理系统',"*"*10) temp = int(input("查看学生信息请选择0,添加请选择1,删除请选择2,修改请选择3,退出选择4:")) if temp ==0: for k,v in dict1.items(): print(k,v) elif temp == 1: name = input("请输入学生姓名:") gender = input("请输入学生性别:") age = input("请输入学生数字年龄:") address = input('请输入学生地址:') lis_temp = [] lis_temp.append(gender) lis_temp.append(age) lis_temp.append(address) dict1[name] = lis_temp print('你成功添加"{}"信息,所以信息如下:'.format(name)) for k, v in dict1.items(): print(k, v) elif temp ==2: name = input("请输入需要删除学生姓名:") del dict1[name] print('移除成功') for k, v in dict1.items(): print(k, v) elif temp ==3: name = input("请输入需要修改学生姓名,如果要修改姓名请删除重新添加:") dict1[name][0]=input("请输入修改学生性别:") dict1[name][1] = input("请输入修改学生数字年龄:") dict1[name][2] = input('请输入修改学生地址:') print('修改成功') for k, v in dict1.items(): print(k, v) elif temp ==4: break # #查询 list1 = ['字符串',10,['abc']] print(list1[2])#使用下标进行查询,下标从0开始 # # #增加 list1 = ['字符串',10,['abc']] temp= 'aaaa' list1.append(temp)#结尾增加元素 print(list1) #插入 list1 = ['字符串',10,['abc']] print('原来的字符串',list1) temp = 'aaaa' list1.insert(1,temp)#在指定位置删除元素 print('插入后字符串',list1) #修改 list1 = ['字符串',10,['abc']] print('原来的字符串',list1) temp = 'aaaa' list1[1]=11 print('插入后字符串',list1) #删除 # list1 = ['字符串',10,['abc']] # print('原来的字符串',list1) # list1.remove(10)#移除指定元素 # list1.pop(0)#弹出指定元素,如果不带参数,弹出最后一个 # print('删除后字符串',list1) #元组 # tuple1 = (1,2,3,4) # for i in tuple1: # print(i) # #元组(不能修改)但是有嵌套(嵌套内部可以修改)的一定要注意 # tuple1 = (1,2,3,4,[1,2,4]) # print(tuple1) # tuple1[4][2]=3 # print(tuple1) # #集合案例 集合是无序的,没有下标,不能用下标索引。 # list1 = [1,2,3,4,5,6,1,2,3,4,5,6,7,] # set1 = {1,2,3,4,5,6,1,2,3,4,5,6,7} # tuple = (1,2,3,4,5,6,1,2,3,4,5,6,7,) # # temp = set(tuple) # temp2 = list(set1) # print(temp) # print(temp2) # # set1.pop() # # list1.pop() # 字典:{'key':'value'} # 函数:系统内置函数,自定义函数 # print() # input() # 案例自定义函数:带参数,不带参数,带返回值,不带返回值 def sum_1(): a=1 b=2 print(a+b) # 案例带参数,并且默认参数 def sum_2(a=0,b=0): print(a+b) # 案例 带参数:默认,1个参数,多个参数,不定长参数。 def add(a,b): print(a+b) def abc(*args,**kwargs): if len(args) > 1: print(sum(args)) else: print(kwargs) # 不定长参数案例 def abc(a,b,*args,**kwargs):#定义可变长函数 print("参数a={},b={},args={},kwargs={}".format(a,b,args,kwargs)) abc(1,2,3,4,5,6,7,[1,2,3,],(1,2,3),p=0,k=1) #函数调用 #带返回值函数 # 带参数+带返回值 def add(a,b): temp = a+b return temp print(add(1,2)) # 无参数,有返回值 def add(): a=10 b=20 return a+b temp = add() print(temp) #无参数,有返回值 def abc(): return {"abc":10} temp = abc() # # print(temp) # 有参数,有返回值 def abc(a,b): return {a:b} temp = abc('king',10) print(temp) # 学生管理系统案例(函数版本) dict1 = {'姓名':['性别','年龄','地址'],'King':['men',10,'毕节']} temp=0 def suru(): """这个函数的目的是输入选择数字""" print("0:查询,1:增加,2:删除,3:修改,4:退出") global temp temp = int(input("请输入一个数字")) def chaxun(): """查询数据库中的信息""" for k,v in dict1.items(): print(k,v) def abc(): '''添加到数据库''' xingbie = input('请输入性别') nianl = input("请输入年龄") dizhi = input("请输入地址") dict1[xingming] = [xingbie, nianl, dizhi] while True: suru() if temp == 0: chaxun() elif temp == 1: xingming = input("请输入要添加的姓名") abc() chaxun() elif temp == 2: xingming = input("请输入要添加的姓名") if xingming in dict1.keys(): del dict1[xingming] else: print('没有此人,无法删除') chaxun() elif temp == 3: xingming = input("请输入要添加的姓名") if xingming in dict1.keys(): abc() chaxun() else: print('没有此人,无法修改') elif temp == 4: break else: print("你输入错误,请重新输入")
    Processed: 0.012, SQL: 9