JavaScript练习:查找字符串中唯一字母的数量

    技术2022-07-11  142

    Everyone once in a while it's good to complete a fun vanilla JavaScript exercise. One recent exercise I tried was to find the number of occurrences of each letter in specified string. The following was my method.

    每个人偶尔都要完成一个有趣的原始JavaScript练习。 我尝试的最近一项练习是查找指定字符串中每个字母的出现次数。 以下是我的方法。

    JavaScript (The JavaScript)

    /* returns the size/length of an object */ Object.size = function(obj) { var size = 0; for(key in obj) { if(obj.hasOwnProperty(key)) size++; } return size; } //initial vars var str = 'hellodavidthisisatestofobjectusage'; var letters = new Object; //loop, figure it out for(x = 0, length = str.length; x < length; x++) { var l = str.charAt(x) letters[l] = (isNaN(letters[l]) ? 1 : letters[l] + 1); } //output count! for(key in letters) { console.log(key + ' :: ' + letters[key]); } console.log(Object.size(letters));

    结果 (The Result)

    h :: 2 e :: 4 l :: 2 o :: 3 d :: 2 a :: 3 v :: 1 i :: 3 t :: 4 s :: 4 f :: 1 b :: 1 j :: 1 c :: 1 u :: 1 g :: 1 16

    The above results in 20 letters being found

    上面的结果是找到20个字母

    Have a different solution? Share it!

    有其他解决方案吗? 分享它!

    翻译自: https://davidwalsh.name/javascript-unique-letters-string

    相关资源:javascript入门笔记
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